Accept number and check the number is even or odd finds the length of the number sum of the digits in the number

clear
echo "Enter number:"
read no;
count=0
total=0
while [ $no -ne 0 ]
do
 a=`expr $no % 10`
 no=`expr $no / 10`
 total=`expr $total + $a`
 count=`expr $count + 1`
done
if [ `expr $no % 2` -eq 0  ]; then
 echo "NUMBER IS EVEN"
else
 echo "NUMBER IS ODD"
fi
echo "SUM OF ALL DIGITS:$total"
echo "TOTAL NUMBER OF DIGIT:$count" 

Output: